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Ncert solutions

CHAPTERS

EXERCISES

1. Surface Areas and Volumes - Exercise 13.1

2. Surface Areas and Volumes - Exercise 13.2

3. Surface Areas and Volumes - Exercise 13.3

4. Surface Areas and Volumes - Exercise 13.4

5. Surface Areas and Volumes - Exercise 13.5

6. Surface Areas and Volumes - Exercise 13.6

7. Surface Areas and Volumes - Exercise 13.7

A cuboidal water tank is 6 m long, 5 m wide and 4.5 m deep. How many liters of water can

Does it hold? \left(1 \mathrm{m}^{3}=1000 \mathrm{l}\right)

Dimensions of a cuboidal water tank are: l = 6 m and b = 5 m and h = 4.5 m

Formula to find the volume of the tank , V = l x b x h

Put the values, we get

V = (6 x 5 x 4.5) = 135

A cuboidal water tank is 6 m long, 5 m wide and 4.5 m deep. How many liters of water can

Does it hold? \left(1 \mathrm{m}^{3}=1000 \mathrm{l}\right)

Dimensions of a cuboidal water tank are: l = 6 m and b = 5 m and h = 4.5 m

Formula to find the volume of the tank , V = l x b x h

Put the values, we get

V = (6 x 5 x 4.5) = 135

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